12 7 Power In Electric Circuits Mremrich Com-Books Pdf

12 7 POWER IN ELECTRIC CIRCUITS mremrich com
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b P 1200 W P VI, V 1 2 102 V P, 4 P 360 W V, 5 I 2 0 A P I 2R. P 2 0 A 22, Understanding Concepts, 6 a P 60 0 W 0 0600 kW E P t. t 1 00 h 0 0600 kW 1 00 h, E E 0 0600 kW h, cost 0 0600 kW h 8 9 kW h. cost 0 534, b P 60 0 W or 0 0600 kW E P t, t 1 0 d or 24 h 0 0600 kW 24 h. E E 1 44 kW h, cost 1 44 kW h 8 9 kW h, c P 60 0 W 0 0600 kW E P t.
t 1 00 a 8 77 103 h 0 0600 kW 8 77 103 h, E 526 kW h. cost 526 kW h 8 9 kW h, cost 4681 or 46 81, V 120 V 120 V 1 2 A. P 1 4 10 2 W or 0 14 kW, t 2 0 h 30 60 h E P t, E 0 14 kW 60 h. E 8 6 kW h, cost 8 6 kW h 8 5 kW h, 8 P 120 W 0 12 kW E P t. t 15 min or 0 25 h 365 d 91 h 0 12 kW 91 h, E E 11 kW h.
cost 11 kW h 9 2 kW h, cost 101 or 1 01, 312 Unit 5 Electricity and Magnetism Copyright 2002 Nelson Thomson Learning. Section 12 7 Questions, Understanding Concepts, V 120 V 120 V 5 0 A. P 6 0 102 W or 0 60 kW, t 3 0 h E P t, E 0 60 kW 3 0 h. E 1 8 kW h, cost 1 8 kW h 8 8 kW h, 2 P 250 W 0 25 kW E P t. t 5 min 48 30 or 7200 min 60 min h 120 h 0 25 kW 120 h. E E 30 kW h, cost 30 kW h 9 4 kW h, cost 282 or 2 82.
3 For the coffee percolator V, P 960 W or 0 96 kW, t 0 5 30 h 15 h E P t. E 0 96 kW 30 h, For the electric drill E P t, P 250 W 0 25 kW 0 25 kW 60 h. t 2 0 30 h 60 h, For the toaster P VI, I 5 0 A 120 V 5 0 A. P 600 W or 0 60 kW, t 0 25 30 h 7 5 h E P t, E 0 60 kW 7 5 h. E 4 5 kW h, The total energy use is 29 kW h 15 kW h 4 5 kW h 48 5 kW h.
cost 48 5 kW h 9 0 kW h, cost 437 or 4 37, 4 P 1250 W P VI. The potential difference across the heater is 240 V. Copyright 2002 Nelson Thomson Learning Chapter 12 Electricity 313. 5 For the toaster P VI, P 7 0 102 W P, For the kettle P VI. P 1100 W P, The total current is 5 8 A 9 2 A 15 A, V 120 V 120 V 20 0 A. I 20 0 A 3, P 2 4 10 W, The maximum power is 2 4 103 W. t 10 0 min or 600 s Q I t, 8 0 A 600 s, Q 4 8 10 3 C.
The quantity of charge that flows through the heater is 4 8 103 C. b E E VI t, I 8 0 A 120 V 8 0 A 600 s, t 10 0 min or 600 s. E 5 8 105 J, The heater would use 5 8 105 J of energy. This value could also be expressed as 0 16 kW h, I 8 0 A 120 V 8 A. The power dissipated is 9 6 102 W, 8 Summarized in a table. Power rating Time used in Energy used kW h, kW one month h E P t.
television 0 08 90 7 2, computer 0 2 45 9, VCR 0 04 8 0 32. stereo 0 03 80 2 4, washer 0 5 4 2, dryer 5 0 4 20. microwave 0 75 1 0 75, TOTAL 41 67, cost 42 kW h 9 2 kW h 386 or 3 86. 314 Unit 5 Electricity and Magnetism Copyright 2002 Nelson Thomson Learning. 9 The total resistance of the circuit, Applying Ohm s law to the entire circuit. a The total power of the circuit, R 16 1 1 A 16, b For the 12 resistor.
R 12 1 1 A 12, For the 4 0 resistor, R 4 0 1 1 A 4 0. The power dissipated by each resistor is equal to the sum of the total power of the circuit. 10 The total resistance of the circuit, Applying Ohm s law to the entire circuit. a The total power of the circuit, R 3 0 6 0 A 3 0, The total power of the circuit is 1 1 102 W. Copyright 2002 Nelson Thomson Learning Chapter 12 Electricity 315. b For the 12 resistor, Applying Ohm s law, R 12 1 5 A 2 12. For the 4 0 resistor, Applying Ohm s law, R 4 0 4 5 A 2 4 0.
The power dissipated by each resistor is equal to the sum of the total power of the circuit. Applying Inquiry Skills, 11 b m 250 g or 0 25 kg Q mc w t. cw 4 18 103 J kg C 0 25 kg 4 18 103 J kg C 70 C, t 85 C 15 C 70 C. Q Q 7 3 10 4 J, The total energy transferred is 7 3 104 J. 7 3 10 4 J, P 3 0 102 W, Making Connections, 12 When appliances are connected in parallel you know exactly the amount of voltage each one will be receiving You can. also control each one with a separate switch and the only limit to the number you have connected is the current rating of. the wire If appliances were connected in series they would all have to be on and the different resistances of each one. would cause unknown values of voltage at each appliance. 13 The service charges such as mailing a bill and reading the meter to operate the home are fixed so a higher rate is. charged to cover these fees Once you have sold a certain amount of electricity to that home the remaining usage is more. profitable and you can offer customers who use a large quantity a discount. 316 Unit 5 Electricity and Magnetism Copyright 2002 Nelson Thomson Learning. 14 In the middle of winter electric furnaces are running and the days are shorter so the lights will be on longer In the. summer fans and or air conditioners are running to cool the houses off Both of these will cause an increase in the amount. of electricity used in your home, CHAPTER 12 REVIEW.
Pages 468 469, Understanding Concepts, 1 a The term elementary charge refers to the smallest charge that exists that cannot be reduced It is much like the term. atom as the smallest part of an element such as gold. b N 3 0 1011 electrons Q Ne, e 1 6 10 C 3 0 1011 1 6 10 19 C. Q 4 8 10 8 C, e 1 6 10 19 C Q, Q 0 30 C N, 1 6 10 19 C. N 1 9 1018, The object has lost 1 9 10 electrons, 2 a The charge will be shared by the objects so a total of 0 020 2 0 010 C will move. e 1 6 10 C Q, 1 6 10 19 C, N 6 3 1016 electrons, b The electrons will move from the neutral object onto the positively charged object.
3 Applying Kirchhoff s voltage law, V0 V1 V3 V4 V0 V1 V3 V5 V0 V1 V2 V4. 72 0 V 36 0 V 20 0 V V4 72 0 V 36 0 V 20 0 V V5 72 0 V 36 0 V V2 16 0 V. V4 16 0 V V5 16 0 V V2 20 0 V, Applying Kirchhoff s current law. I1 I 2 I 3 I1 I 4 I 5, 2 0 A 4 0 A 6 0 A I 4 5 0 A. I1 6 0 A I 4 1 0 A, I 0 30 A t, t 5 0 min or 300 s Q I t. 0 30 A 300 s, 90 C of charge passes through the device.
5 Q 1 8 C Q, I 9 5 mA or 9 5 10 3 A t, 9 5 10 3 A, t 1 9 102 s. Copyright 2002 Nelson Thomson Learning Chapter 12 Electricity 317. http www factsfacts com MyHomeRepair DimmerSwitch htm 12 7 POWER IN ELECTRIC CIRCUITS PRACTICE Page 463 Understanding Concepts 1 P V 120 V I 4 6 A

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